This documentation is automatically generated by online-judge-tools/verification-helper
#define PROBLEM "https://judge.yosupo.jp/problem/count_points_in_triangle"
#include "../misc/macros.h"
#include "../geometry/TrianglePointCount.h"
using P = Point<i64>;
void solve() {
vector<P> A, B;
int n, m;
cin >> n;
A.resize(n);
for (auto& [x, y] : A) cin >> x >> y;
cin >> m;
B.resize(m);
for (auto& [x, y] : B) cin >> x >> y;
TrianglePointCount<P, 500, 500> tpc(A, B);
int q;
cin >> q;
while (q--) {
int a, b, c;
cin >> a >> b >> c;
cout << tpc.query(a, b, c) << '\n';
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int tc = 1;
// cin >> tc;
while (tc--) solve();
}#line 1 "tests/Count_Points_in_Triangle.test.cpp"
#define PROBLEM "https://judge.yosupo.jp/problem/count_points_in_triangle"
#line 1 "misc/macros.h"
// #pragma GCC optimize("Ofast,unroll-loops") // unroll long, simple loops
// #pragma GCC target("avx2,fma") // vectorizing code
// #pragma GCC target("lzcnt,popcnt,abm,bmi,bmi2") // for fast bitset operation
#include <bits/extc++.h>
#include <tr2/dynamic_bitset>
using namespace std;
using namespace __gnu_pbds; // ordered_set, gp_hash_table
// using namespace __gnu_cxx; // rope
// for templates to work
#define all(x) (x).begin(), (x).end()
#define sz(x) (int) (x).size()
#define pb push_back
#define eb emplace_back
using i32 = int32_t;
using u32 = uint32_t;
using i64 = int64_t;
using u64 = uint64_t;
using i128 = __int128_t;
using u128 = __uint128_t;
using ld = long double;
using pii = pair<i32, i32>;
using vi = vector<i32>;
// fast map
const int RANDOM = chrono::high_resolution_clock::now().time_since_epoch().count();
struct chash { // customize hash function for gp_hash_table
int operator()(int x) const { return x ^ RANDOM; }
};
gp_hash_table<int, int, chash> table;
/* ordered set
find_by_order(k): returns an iterator to the k-th element (0-based)
order_of_key(k): returns the number of elements in the set that are strictly less than k
*/
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
/* rope
rope <int> cur = v.substr(l, r - l + 1);
v.erase(l, r - l + 1);
v.insert(v.mutable_begin(), cur);
*/
#line 2 "geometry/Point.h"
template <class T>
int sgn(T x) { return (x > 0) - (x < 0); }
template <class T>
struct Point {
typedef Point P;
T x, y;
explicit Point(T x = 0, T y = 0) : x(x), y(y) {}
bool operator<(P p) const { return tie(x, y) < tie(p.x, p.y); }
bool operator==(P p) const { return tie(x, y) == tie(p.x, p.y); }
P operator+(P p) const { return P(x + p.x, y + p.y); }
P operator-(P p) const { return P(x - p.x, y - p.y); }
P operator*(T d) const { return P(x * d, y * d); }
P operator/(T d) const { return P(x / d, y / d); }
T dot(P p) const { return x * p.x + y * p.y; }
T cross(P p) const { return x * p.y - y * p.x; }
T cross(P a, P b) const { return (a - *this).cross(b - *this); }
T dist2() const { return x * x + y * y; }
T dist() const { return sqrt(dist2()); }
// angle to x-axis in interval [-pi, pi]
T angle() const { return atan2l(y, x); }
P unit() const { return *this / dist(); } // makes dist()=1
P perp() const { return P(-y, x); } // rotates +90 degrees
P normal() const { return perp().unit(); }
// returns point rotated 'a' radians ccw around the origin
P rotate(ld a) const {
return P(x * cos(a) - y * sin(a), x * sin(a) + y * cos(a));
}
friend ostream& operator<<(ostream& os, P p) {
return os << "(" << p.x << "," << p.y << ")";
}
};
#line 2 "geometry/TrianglePointCount.h"
template <class P, int MAXN, int MAXM>
struct TrianglePointCount {
// Bảng lưu trạng thái: side[i][j] = bitset các điểm B nằm bên trái vector A[i]->A[j]
bitset<MAXM> side[MAXN][MAXN];
const vector<P>& A; // Tham chiếu tới mảng A để kiểm tra hướng khi truy vấn
// Constructor: Thực hiện Precomputation O(N^2 * M)
TrianglePointCount(const vector<P>& A, const vector<P>& B)
: A(A) {
int n = sz(A), m = sz(B);
for (int i = 0; i < n; ++i) {
for (int j = 0; j < n; ++j) {
if (i == j) continue;
P vecIJ = A[j] - A[i]; // Vector A[i] -> A[j]
for (int k = 0; k < m; ++k) {
P vecIK = B[k] - A[i]; // Vector A[i] -> B[k]
// Nếu B[k] nằm thực sự bên trái A[i]->A[j] (cross product > 0)
if (vecIJ.cross(vecIK) > 0) side[i][j][k] = 1;
}
}
}
}
// Truy vấn: Đếm số điểm B nằm trong tam giác A[a], A[b], A[c]
// Độ phức tạp: O(M/64) ~ O(1)
int query(int a, int b, int c) {
// Kiểm tra hướng của tam giác
auto area = A[a].cross(A[b], A[c]);
if (area == 0) return 0; // Tam giác suy biến (thẳng hàng)
if (area > 0) {
// Ngược chiều kim đồng hồ (CCW): A->B->C
// Điểm trong tam giác phải nằm trái AB, trái BC, VÀ trái CA
return (side[a][b] & side[b][c] & side[c][a]).count();
} else {
// Cùng chiều kim đồng hồ (CW): A->C->B là CCW
return (side[a][c] & side[c][b] & side[b][a]).count();
}
}
};
#line 5 "tests/Count_Points_in_Triangle.test.cpp"
using P = Point<i64>;
void solve() {
vector<P> A, B;
int n, m;
cin >> n;
A.resize(n);
for (auto& [x, y] : A) cin >> x >> y;
cin >> m;
B.resize(m);
for (auto& [x, y] : B) cin >> x >> y;
TrianglePointCount<P, 500, 500> tpc(A, B);
int q;
cin >> q;
while (q--) {
int a, b, c;
cin >> a >> b >> c;
cout << tpc.query(a, b, c) << '\n';
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int tc = 1;
// cin >> tc;
while (tc--) solve();
}