This documentation is automatically generated by online-judge-tools/verification-helper
#define PROBLEM "https://judge.yosupo.jp/problem/closest_pair"
#include "../misc/macros.h"
#include "../geometry/ClosestPair.h"
void solve() {
int n;
cin >> n;
vector<Point<i64>> p(n);
for (int i = 0; i < n; ++i) cin >> p[i].x >> p[i].y;
auto ans = closest(p);
int p1, p2;
for (int i = 0; i < n; ++i) {
if (p[i] == ans.first) {
p1 = i;
break;
}
}
for (int i = 0; i < n; ++i) {
if (i != p1 && p[i] == ans.second) {
p2 = i;
break;
}
}
cout << p1 << ' ' << p2 << '\n';
}
int main() {
cin.tie(0)->sync_with_stdio(0);
cin.exceptions(cin.failbit);
int tc = 1;
cin >> tc;
for (int i = 1; i <= tc; ++i) {
solve();
}
}#line 1 "tests/Closest_Pair_of_Points.test.cpp"
#define PROBLEM "https://judge.yosupo.jp/problem/closest_pair"
#line 1 "misc/macros.h"
// #pragma GCC optimize("Ofast,unroll-loops") // unroll long, simple loops
// #pragma GCC target("avx2,fma") // vectorizing code
// #pragma GCC target("lzcnt,popcnt,abm,bmi,bmi2") // for fast bitset operation
#include <bits/extc++.h>
#include <tr2/dynamic_bitset>
using namespace std;
using namespace __gnu_pbds; // ordered_set, gp_hash_table
// using namespace __gnu_cxx; // rope
// for templates to work
#define all(x) (x).begin(), (x).end()
#define sz(x) (int) (x).size()
#define pb push_back
#define eb emplace_back
using i32 = int32_t;
using u32 = uint32_t;
using i64 = int64_t;
using u64 = uint64_t;
using i128 = __int128_t;
using u128 = __uint128_t;
using ld = long double;
using pii = pair<i32, i32>;
using vi = vector<i32>;
// fast map
const int RANDOM = chrono::high_resolution_clock::now().time_since_epoch().count();
struct chash { // customize hash function for gp_hash_table
int operator()(int x) const { return x ^ RANDOM; }
};
gp_hash_table<int, int, chash> table;
/* ordered set
find_by_order(k): returns an iterator to the k-th element (0-based)
order_of_key(k): returns the number of elements in the set that are strictly less than k
*/
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
/* rope
rope <int> cur = v.substr(l, r - l + 1);
v.erase(l, r - l + 1);
v.insert(v.mutable_begin(), cur);
*/
#line 2 "geometry/Point.h"
template <class T>
int sgn(T x) { return (x > 0) - (x < 0); }
template <class T>
struct Point {
typedef Point P;
T x, y;
explicit Point(T x = 0, T y = 0) : x(x), y(y) {}
bool operator<(P p) const { return tie(x, y) < tie(p.x, p.y); }
bool operator==(P p) const { return tie(x, y) == tie(p.x, p.y); }
P operator+(P p) const { return P(x + p.x, y + p.y); }
P operator-(P p) const { return P(x - p.x, y - p.y); }
P operator*(T d) const { return P(x * d, y * d); }
P operator/(T d) const { return P(x / d, y / d); }
T dot(P p) const { return x * p.x + y * p.y; }
T cross(P p) const { return x * p.y - y * p.x; }
T cross(P a, P b) const { return (a - *this).cross(b - *this); }
T dist2() const { return x * x + y * y; }
T dist() const { return sqrt(dist2()); }
// angle to x-axis in interval [-pi, pi]
T angle() const { return atan2l(y, x); }
P unit() const { return *this / dist(); } // makes dist()=1
P perp() const { return P(-y, x); } // rotates +90 degrees
P normal() const { return perp().unit(); }
// returns point rotated 'a' radians ccw around the origin
P rotate(ld a) const {
return P(x * cos(a) - y * sin(a), x * sin(a) + y * cos(a));
}
friend ostream& operator<<(ostream& os, P p) {
return os << "(" << p.x << "," << p.y << ")";
}
};
#line 2 "geometry/ClosestPair.h"
typedef Point<i64> P;
pair<P, P> closest(vector<P> v) {
assert(sz(v) > 1);
set<P> S;
sort(all(v), [](P a, P b) { return a.y < b.y; });
pair<i64, pair<P, P>> ret{LLONG_MAX, {P(), P()}};
int j = 0;
for (P p : v) {
P d{1 + (i64)sqrt(ret.first), 0};
while (v[j].y <= p.y - d.x) S.erase(v[j++]);
auto lo = S.lower_bound(p - d), hi = S.upper_bound(p + d);
for (; lo != hi; ++lo) ret = min(ret, {(*lo - p).dist2(), {*lo, p}});
S.insert(p);
}
return ret.second;
}
#line 5 "tests/Closest_Pair_of_Points.test.cpp"
void solve() {
int n;
cin >> n;
vector<Point<i64>> p(n);
for (int i = 0; i < n; ++i) cin >> p[i].x >> p[i].y;
auto ans = closest(p);
int p1, p2;
for (int i = 0; i < n; ++i) {
if (p[i] == ans.first) {
p1 = i;
break;
}
}
for (int i = 0; i < n; ++i) {
if (i != p1 && p[i] == ans.second) {
p2 = i;
break;
}
}
cout << p1 << ' ' << p2 << '\n';
}
int main() {
cin.tie(0)->sync_with_stdio(0);
cin.exceptions(cin.failbit);
int tc = 1;
cin >> tc;
for (int i = 1; i <= tc; ++i) {
solve();
}
}